Здравейте, борим се с един приятел по сайта му на Opencart 1.5.5.1 със следната грешка в лога.
2015-02-16 15:15:01 - PHP Notice: Error: Duplicate entry '4' for key 'PRIMARY'<br />Error No: 1062<br />INSERT INTO oc_custom_title_other SET custom_title_id= '4',other_id = '127',language_id = '2', title = 'name product', keyword = '', description = '',type = '4' in /h2/home/tr/public_html/system/database/mysql.php on line 50
50-ти ред е: trigger_error('Error: ' . mysql_error($this->link) . '<br />Error No: ' . mysql_errno($this->link) . '<br />' . $sql);
Грешката се появява когато реши да дублира (Създай подобен ) продукт в админа.
Бихме се радвали, ако някой помогне, защото моите познания не стигат в тази насока.
Благодаря!
Ето и файла public_html/system/database/mysql.php
<?php
final class MySQL {
private $link;
public function __construct($hostname, $username, $password, $database) {
if (!$this->link = mysql_connect($hostname, $username, $password)) {
trigger_error('Error: Could not make a database link using ' . $username . '@' . $hostname);
}
if (!mysql_select_db($database, $this->link)) {
trigger_error('Error: Could not connect to database ' . $database);
}
mysql_query("SET NAMES 'utf8'", $this->link);
mysql_query("SET CHARACTER SET utf8", $this->link);
mysql_query("SET CHARACTER_SET_CONNECTION=utf8", $this->link);
mysql_query("SET SQL_MODE = ''", $this->link);
}
public function query($sql) {
if ($this->link) {
$resource = mysql_query($sql, $this->link);
if ($resource) {
if (is_resource($resource)) {
$i = 0;
$data = array();
while ($result = mysql_fetch_assoc($resource)) {
$data[$i] = $result;
$i++;
}
mysql_free_result($resource);
$query = new stdClass();
$query->row = isset($data[0]) ? $data[0] : array();
$query->rows = $data;
$query->num_rows = $i;
unset($data);
return $query;
} else {
return true;
}
} else {
trigger_error('Error: ' . mysql_error($this->link) . '<br />Error No: ' . mysql_errno($this->link) . '<br />' . $sql);
exit();
}
}
}
public function escape($value) {
if ($this->link) {
return mysql_real_escape_string($value, $this->link);
}
}
public function countAffected() {
if ($this->link) {
return mysql_affected_rows($this->link);
}
}
public function getLastId() {
if ($this->link) {
return mysql_insert_id($this->link);
}
}
public function __destruct() {
if ($this->link) {
mysql_close($this->link);
}
}
}
?>
2015-02-16 15:15:01 - PHP Notice: Error: Duplicate entry '4' for key 'PRIMARY'<br />Error No: 1062<br />INSERT INTO oc_custom_title_other SET custom_title_id= '4',other_id = '127',language_id = '2', title = 'name product', keyword = '', description = '',type = '4' in /h2/home/tr/public_html/system/database/mysql.php on line 50
50-ти ред е: trigger_error('Error: ' . mysql_error($this->link) . '<br />Error No: ' . mysql_errno($this->link) . '<br />' . $sql);
Грешката се появява когато реши да дублира (Създай подобен ) продукт в админа.
Бихме се радвали, ако някой помогне, защото моите познания не стигат в тази насока.
Благодаря!
Ето и файла public_html/system/database/mysql.php
<?php
final class MySQL {
private $link;
public function __construct($hostname, $username, $password, $database) {
if (!$this->link = mysql_connect($hostname, $username, $password)) {
trigger_error('Error: Could not make a database link using ' . $username . '@' . $hostname);
}
if (!mysql_select_db($database, $this->link)) {
trigger_error('Error: Could not connect to database ' . $database);
}
mysql_query("SET NAMES 'utf8'", $this->link);
mysql_query("SET CHARACTER SET utf8", $this->link);
mysql_query("SET CHARACTER_SET_CONNECTION=utf8", $this->link);
mysql_query("SET SQL_MODE = ''", $this->link);
}
public function query($sql) {
if ($this->link) {
$resource = mysql_query($sql, $this->link);
if ($resource) {
if (is_resource($resource)) {
$i = 0;
$data = array();
while ($result = mysql_fetch_assoc($resource)) {
$data[$i] = $result;
$i++;
}
mysql_free_result($resource);
$query = new stdClass();
$query->row = isset($data[0]) ? $data[0] : array();
$query->rows = $data;
$query->num_rows = $i;
unset($data);
return $query;
} else {
return true;
}
} else {
trigger_error('Error: ' . mysql_error($this->link) . '<br />Error No: ' . mysql_errno($this->link) . '<br />' . $sql);
exit();
}
}
}
public function escape($value) {
if ($this->link) {
return mysql_real_escape_string($value, $this->link);
}
}
public function countAffected() {
if ($this->link) {
return mysql_affected_rows($this->link);
}
}
public function getLastId() {
if ($this->link) {
return mysql_insert_id($this->link);
}
}
public function __destruct() {
if ($this->link) {
mysql_close($this->link);
}
}
}
?>